Conic Sections Question 159
Question: The equation of the tangent to the conic $ x^{2}-y^{2}-8x+2y+11=0 $ at (2, 1) is
[Karnataka CET 1993]
Options:
A) $ x+2=0 $
B) $ 2x+1=0 $
C) $ x-2=0 $
D) $ x+y+1=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
Equation of the tangent to $ x^{2}-y^{2}-8x+2y+11=0 $ at (2, 1) is $ 2x-y-4(x+2)+ $
$ (y+1)+11=0 $ or $ x=2 $ .
BETA
