Conic Sections Question 162
Question: The normal to the parabola $ y^{2}=8x $ at the point (2, 4) meets the parabola again at the point
[Orissa JEE 2003]
Options:
A) {-18, -12}
B) {-18, 12}
C) {18, 12}
D) (18, -12)
Show Answer
Answer:
Correct Answer: D
Solution:
We have $ t_2=-t_1-\frac{2}{t_1} $
Since $ a=2,t_1=1 $ ;
$ \therefore $ $ t_2=-3 $
$ \therefore $ The other end will be $ (at_2^{2},2at_2) $ i.e., (18, - 12).
BETA
