Conic Sections Question 167
Question: The area of triangle formed inside the parabola $ y^{2}=4x $ and whose ordinates of vertices are 1, 2 and 4 will be
[RPET 1990]
Options:
A) $ \frac{7}{2} $
B) $ \frac{5}{2} $
C) $ \frac{3}{2} $
D) $ \frac{3}{4} $
Show Answer
Answer:
Correct Answer: D
Solution:
Let co-ordinates of vertices $ =(a,1),(b,2),(c,4) $
$ a=\frac{1}{4}, $
$ b=1,c=4 $ . Area of triangle formed by $ ( \frac{1}{4},1 ),(1,2),(4,4) $ is $ \frac{1}{2} \begin{vmatrix} 1/4 & 1 & 1 \\ 1 & 2 & 1 \\ 4 & 4 & 1 \\ \end{vmatrix} =\frac{3}{2} $ .
BETA
