Conic Sections Question 180
Question: The ends of the latus rectum of the conic $ x^{2}+10x-16y+25=0 $ are
[Karnataka CET 2005]
Options:
A) (3, -4), (13, 4)
B) (-3, -4), (13, -4)
C) (3, 4), (-13, 4)
D) (5, -8), (-5, 8)
Show Answer
Answer:
Correct Answer: C
Solution:
Equation of conic is $ x^{2}+10x-16y+25=0 $ i.e., $ {{(x+5)}^{2}}=16y $ . Conic is parabola with focus (-5, 4) $ \because $ focus is mid point of latus rectum. only points given in option (c) can be end points of the latus rectum.
BETA
