Conic Sections Question 186
Question: The equation to a parabola which passes through the intersection of a straight line $ x+y=0 $ and the circle $ x^{2}+y^{2}+4y=0 $ is
[Orissa JEE 2005]
Options:
A) $ y^{2}=4x $
B) $ y^{2}=x $
C) $ y^{2}=2x $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Given $ x+y=0 $ …..(i) $ x^{2}+y^{2}+4y=0 $ ….. (ii) Solving (i) and (ii), $ x=0 $ , $ y=0 $ ; $ x=2 $ , $ y=-2 $ which means parabola pass through (0, 0) and (2, -2) these points satisfy the parabola $ y^{2}=2x $ .
BETA
