Conic Sections Question 189
Question: The equation of a straight line drawn through the focus of the parabola $ y^{2}=-4x $ at an angle of 120° to the x-axis is
[Orissa JEE 2005]
Options:
A) $ y+\sqrt{3}(x-1)=0 $
B) $ y-\sqrt{3}(x-1)=0 $
C) $ y+\sqrt{3}(x+1)=0 $
D) $ y-\sqrt{3}(x+1)=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ m=\tan (120{}^\circ )=-\sqrt{3} $ = Slope of the line which passes through (-1, 0). Required equation, $ y-0=-\sqrt{3}(x+1) $
$ y+\sqrt{3}(x+1)=0 $ .
BETA
