Conic Sections Question 19
Question: The length of latus rectum of the parabola $ 4y^{2}+2x-20y+17=0 $ is
[MP PET 1999]
Options:
A) 3
B) 6
C) $ \frac{1}{2} $
D) 9
Show Answer
Answer:
Correct Answer: C
Solution:
$ 4y^{2}+2x-20y+17=0 $
$ 2{{( y-\frac{5}{2} )}^{2}}=-(x-4) $
therefore $ 4a=\frac{1}{2} $ .