Conic Sections Question 19

Question: The length of latus rectum of the parabola $ 4y^{2}+2x-20y+17=0 $ is

[MP PET 1999]

Options:

3

6

C) $ \frac{1}{2} $

9

Show Answer

Answer:

Correct Answer: C

Solution:

$ 4y^{2}+2x-20y+17=0 $

$ 2{{( y-\frac{5}{2} )}^{2}}=-(x-4) $

therefore $ 4a=\frac{1}{2} $ .



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