Conic Sections Question 190

Question: The equation of an ellipse whose focus (-1, 1), whose directrix is $ x-y+3=0 $ and whose eccentricity is $ \frac{1}{2} $ , is given by

[MP PET 1993]

Options:

A) $ 7x^{2}+2xy+7y^{2}+10x-10y+7=0 $

B) $ 7x^{2}-2xy+7y^{2}-10x+10y+7=0 $

C) $ 7x^{2}-2xy+7y^{2}-10x-10y-7=0 $

D) $ 7x^{2}-2xy+7y^{2}+10x+10y-7=0 $

Show Answer

Answer:

Correct Answer: A

Solution:

Let any point on it be (x, y), then $ \frac{\sqrt{{{(x+1)}^{2}}}+\sqrt{{{(y-1)}^{2}}}}{| \frac{x-y+3}{\sqrt{2}} |}=\frac{1}{2} $

Squaring and simplifying, we get $ 7x^{2}+2xy+7y^{2}+10x-10y+7=0 $ .



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