SATHEE: Conic Sections Question 22

Conic Sections Question 22

Question: The vertex of the parabola $ 3x-2y^{2}-4y+7=0 $ is

[RPET 1996]

Options:

A) (3, 1)

B) (-3, -1)

C) (-3, 1)

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Given equation can be written as, $ {{(y+1)}^{2}}=\frac{3}{2}(x+3). $ So, vertex is $ (-3,-1) $ .

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Conic Sections Question 22

Question: The vertex of the parabola $ 3x-2y^{2}-4y+7=0 $ is

Options:

Answer:

Solution:

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