[DCE 1999]
A) (-4, 1)
B) (4, -1)
C) (-4, -1)
D) (4, 1)
Correct Answer: A
Given parabola is $ x^{2}+8x+12y+4=0 $
It can be written as $ {{(x+4)}^{2}}=-12y+12 $
$ \Rightarrow {{(x+4)}^{2}}=-12(y-1) $ ,vertex is $ (-4,1). $
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