Conic Sections Question 282
Question: The equation of the director circle of the hyperbola $ \frac{x^{2}}{16}-\frac{y^{2}}{4}=1 $ is given by
[Karnataka CET 2004]
Options:
A) $ x^{2}+y^{2}=16 $
B) $ x^{2}+y^{2}=4 $
C) $ x^{2}+y^{2}=20 $
D) $ x^{2}+y^{2}=12 $
Show Answer
Answer:
Correct Answer: D
Solution:
Equation of -director-circle- of hyperbola is $ x^{2}+y^{2}=a^{2}-b^{2} $ . Here $ a^{2}=16,b^{2}=4 $
$ \therefore $ $ x^{2}+y^{2}= $ 12 is the required -director circle……
BETA
