Conic Sections Question 282

Question: The equation of the director circle of the hyperbola $ \frac{x^{2}}{16}-\frac{y^{2}}{4}=1 $ is given by

[Karnataka CET 2004]

Options:

A) $ x^{2}+y^{2}=16 $

B) $ x^{2}+y^{2}=4 $

C) $ x^{2}+y^{2}=20 $

D) $ x^{2}+y^{2}=12 $

Show Answer

Answer:

Correct Answer: D

Solution:

Equation of director circle of hyperbola is $ x^{2}+y^{2}=a^{2}-b^{2} $ . Here $ a^{2}=16,b^{2}=4 $

$ \therefore $ $ x^{2}+y^{2}= $ 12 is the required director circle…



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