Conic Sections Question 29
Question: Focus of the parabola $ {{(y-2)}^{2}}=20(x+3) $ is
[Karnataka CET 1999]
Options:
A) (3, -2)
B) (2, -3)
C) (2, 2)
D) (3, 3)
Show Answer
Answer:
Correct Answer: C
Solution:
We know that the standard equation of a parabola is $ {{(y-\beta )}^{2}}=4a(x-\alpha ). $
Comparing the given equation with the standard equation,
we get vertex $ (\alpha ,\beta )=(-3,2) $ and $ a=5 $ .
Therefore focus of the parabola $ (\alpha +a,\beta )=(2,2) $ .
BETA
