Conic Sections Question 290
Question: The centre of $ 14x^{2}-4xy+11y^{2}-44x-58y+71=0 $
[BIT Ranchi 1986]
Options:
A) (2, 3)
B) (2, - 3)
C) (- 2, 3)
D) (- 2, - 3)
Show Answer
Answer:
Correct Answer: A
Solution:
Use formula of centre of conic i.e., $ ( \frac{hf-bg}{ab-h^{2}},\frac{gh-af}{ab-h^{2}} ) $ .