Conic Sections Question 290

Question: The centre of $ 14x^{2}-4xy+11y^{2}-44x-58y+71=0 $

[BIT Ranchi 1986]

Options:

A) (2, 3)

B) (2, - 3)

C) (- 2, 3)

D) (- 2, - 3)

Show Answer

Answer:

Correct Answer: A

Solution:

Use formula of centre of conic i.e., $ ( \frac{hf-bg}{ab-h^{2}},\frac{gh-af}{ab-h^{2}} ) $ .