Conic Sections Question 3
Question: The equation of parabola whose vertex and focus are (0, 4) and (0, 2) respectively, is
[RPET 1987, 89, 90, 91]
Options:
A) $ y^{2}-8x=32 $
B) $ y^{2}+8x=32 $
C) $ x^{2}+8y=32 $
D) $ x^{2}-8y=32 $
Show Answer
Answer:
Correct Answer: C
Solution:
Vertex $ (0,4) $ ; focus $ (0,2) $ ;
$ \therefore $ $ a=2 $
Hence parabola is $ {{(x-0)}^{2}}=-4.2(y-4) $ i.e., $ x^{2}+8y=32 $ .
BETA
