Conic Sections Question 30
Question: The length of the latus rectum of the parabola $ x^{2}-4x-8y+12=0 $ is
[MP PET 2000]
Options:
A) 4
B) 6
C) 8
D) 10
Show Answer
Answer:
Correct Answer: C
Solution:
The given equation of parabola is $ x^{2}-4x-8y+12=0 $
$ \Rightarrow $ $ x^{2}-4x=8y-12 $
$ \Rightarrow $ $ {{(x-2)}^{2}}=8(y-1) $
Hence the length of latus rectum = $ 4a=8 $ .
BETA
