Conic Sections Question 321
Question: In the ellipse $ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 $ , the equation of diameter conjugate to the diameter $ y=\frac{b}{a}x $ , is
Options:
A) $ y=-\frac{b}{a}x $
B) $ y=-\frac{a}{b}x $
C) $ x=-\frac{b}{a}y $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ y=\frac{-b}{a}x $ (Two diameter $ y=m_1x $ and $ y=m_2x $ will be conjugate diameter, if $ m_1m_2=-\frac{b^{2}}{a^{2}} $ ).
BETA
