[MNR 1981]
A) $ 3/\sqrt{7} $
B) 7/16
C) 3/4
D) 4/3
Correct Answer: C
$ \frac{x^{2}}{\frac{112}{16}}+\frac{y^{2}}{\frac{112}{7}}=1 $ . Therefore, $ e=\sqrt{1-\frac{112}{16}.\frac{7}{112}}=\frac{3}{4} $
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