Conic Sections Question 34
Question: The vertex of parabola $ {{(y-2)}^{2}}=16(x-1) $ is
[Karnataka CET 2001]
Options:
A) (2, 1)
B) (1, -2)
C) (-1, 2)
D) (1, 2)
Show Answer
Answer:
Correct Answer: D
Solution:
We know that the standard equation of parabola is $ {{(y-k)}^{2}}=4a(x-h). $
Comparing the given equation with the standard equation, we get $ h=1,k=2 $ and $ 4a=16 $ or $ a=4. $
Therefore vertex of the parabola $ \equiv (h,k)\equiv (1,2) $ .
BETA
