Conic Sections Question 350

Question: For the ellipse $ 3x^{2}+4y^{2}=12 $ , the length of latus rectum is

[MNR 1973]

Options:

A) $ \frac{3}{2} $

B) 3

C) $ \frac{8}{3} $

D) $ \sqrt{\frac{3}{2}} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{x^{2}}{4}+\frac{y^{2}}{3}=1. $ Latus rectum $ =\frac{2b^{2}}{a}=3 $ .