Conic Sections Question 350
Question: For the ellipse $ 3x^{2}+4y^{2}=12 $ , the length of latus rectum is
[MNR 1973]
Options:
A) $ \frac{3}{2} $
B) 3
C) $ \frac{8}{3} $
D) $ \sqrt{\frac{3}{2}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{x^{2}}{4}+\frac{y^{2}}{3}=1. $ Latus rectum $ =\frac{2b^{2}}{a}=3 $ .