Conic Sections Question 351
Question: For the ellipse $ \frac{x^{2}}{64}+\frac{y^{2}}{28}=1 $ , the eccentricity is
[MNR 1974]
Options:
A) $ \frac{3}{4} $
B) $ \frac{4}{3} $
C) $ \frac{1}{\sqrt{7}} $
D) $ \frac{x^{2}}{4}+y^{2}=1 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ e^{2}=1-\frac{b^{2}}{a^{2}} $
therefore $ e^{2}=\frac{36}{64} $
therefore $ e=\frac{3}{4} $ .
BETA
