Conic Sections Question 367
Question: The length of the latus rectum of the ellipse $ 9x^{2}+4y^{2}=1 $ , is
[MP PET 1999]
Options:
A) $ \frac{3}{2} $
B) $ \frac{8}{3} $
C) $ \frac{4}{9} $
D) $ \frac{8}{9} $
Show Answer
Answer:
Correct Answer: C
Solution:
Given ellipse is $ \frac{x^{2}}{{{( \frac{1}{3} )}^{2}}}+\frac{y^{2}}{{{( \frac{1}{2} )}^{2}}}=1 $ Here $ a<b $ ; $ \therefore $ Latus rectum $ =\frac{2a^{2}}{b}=\frac{2\times \frac{1}{9}}{\frac{1}{2}}=\frac{4}{9} $ .
BETA
