Conic Sections Question 375
Question: The sum of the focal distances of any point on the conic $ \frac{x^{2}}{25}+\frac{y^{2}}{16}=1 $ is
[Karnataka CET 2005]
Options:
A) 10
B) 9
C) 41
D) 18
Show Answer
Answer:
Correct Answer: A
Solution:
For any point P on the ellipse have focus S and S¢ $ SP+{S}‘P=2a $
For $ \frac{x^{2}}{25}+\frac{y^{2}}{16}=1 $
Sum of focal distances = 2 X 5 = 10.
BETA
