Conic Sections Question 377
Question: The eccentricity of the ellipse $ 25x^{2}+16y^{2}=400 $ is
[MP PET 2001]
Options:
A) 3/5
B) 1/3
C) 2/5
D) 1/5
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{x^{2}}{16}+\frac{y^{2}}{25}=1 $
$ \Rightarrow a^{2}=b^{2}(1-e^{2}) $
$ \Rightarrow e^{2}=1-\frac{16}{25}\Rightarrow e=3/5 $ .