[Kerala (Engg.) 2005]
A) 2/5
B) 2/3
C) 4/5
D) 3/4
E) 3/5
Correct Answer: E
$ 25{{(x-3)}^{2}}+16y^{2}=400 $
$ \frac{{{(x-3)}^{2}}}{16}+\frac{y^{2}}{25}=1 $
$ e=\sqrt{1-\frac{16}{25}}=\frac{3}{5} $
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