Conic Sections Question 395

Question: A point on the curve $ \frac{x^{2}}{A^{2}}-\frac{y^{2}}{B^{2}}=1 $ is

[MP PET 1988]

Options:

A) $ (A\cos \theta ,\ B\sin \theta ) $

B) $ (A\sec \theta ,\ B\tan \theta ) $

C) $ (A{{\cos }^{2}}\theta ,\ B{{\sin }^{2}}\theta ) $

D) None of these

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Answer:

Correct Answer: B

Solution:

It is obvious.