Conic Sections Question 400
Question: The eccentricity of a hyperbola passing through the points (3, 0), $ (3\sqrt{2},\ 2) $ will be
[MNR 1985; UPSEAT 2000]
Options:
A) $ \sqrt{13} $
B) $ \frac{\sqrt{13}}{3} $
C) $ \frac{\sqrt{13}}{4} $
D) $ \frac{\sqrt{13}}{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{9}{a^{2}}=1 $
therefore $ a=3 $ and $ \frac{18}{a^{2}}-\frac{4}{b^{2}}=1 $
therefore $ b^{2}=4 $
Therefore, $ e=\sqrt{1+\frac{4}{9}}=\frac{\sqrt{13}}{3} $
BETA
