Conic Sections Question 408

Question: The eccentricity of the hyperbola $ x^{2}-y^{2}=25 $ is

[MP PET 1987]

Options:

A) $ \sqrt{2} $

B) $ 1/\sqrt{2} $

C) 2

D) $ 1+\sqrt{2} $

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Answer:

Correct Answer: A

Solution:

$ \frac{x^{2}}{25}-\frac{y^{2}}{25}=1 $ . Eccentricity $ =\sqrt{2} $ as $ a=b $ .