Conic Sections Question 408
Question: The eccentricity of the hyperbola $ x^{2}-y^{2}=25 $ is
[MP PET 1987]
Options:
A) $ \sqrt{2} $
B) $ 1/\sqrt{2} $
C) 2
D) $ 1+\sqrt{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{x^{2}}{25}-\frac{y^{2}}{25}=1 $ . Eccentricity $ =\sqrt{2} $ as $ a=b $ .