Conic Sections Question 413
Question: The locus of the point of intersection of the lines $ bxt-ayt=ab $ and $ bx+ay=abt $ is
Options:
A) A parabola
B) An ellipse
C) A hyperbola
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Multiplying both, we get $ {{(bx)}^{2}}-{{(ay)}^{2}}={{(ab)}^{2}} $
therefore $ \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 $ which is the standard equation of hyperbola.
BETA
