Conic Sections Question 418
Question: If the centre, vertex and focus of a hyperbola be (0, 0), (4, 0) and (6, 0) respectively, then the equation of the hyperbola is
Options:
A) $ 4x^{2}-5y^{2}=8 $
B) $ 4x^{2}-5y^{2}=80 $
C) $ 5x^{2}-4y^{2}=80 $
D) $ 5x^{2}-4y^{2}=8 $
Show Answer
Answer:
Correct Answer: C
Solution:
Centre (0, 0), vertex (4, 0)
therefore and focus
therefore $ ae=4 $
therefore $ e=\frac{3}{2} $ . Therefore $ b= $
Hence required equation is $ \frac{x^{2}}{16}-\frac{y^{2}}{20}=1 $
i.e., $ 5x^{2}-4y^{2}=80 $ .
BETA
