Conic Sections Question 421
Question: The locus of the point of intersection of the lines $ \sqrt{3}x-y-4\sqrt{3}k=0 $ and $ \sqrt{3}kx+ky-4\sqrt{3}=0 $ for different value of k is
Options:
A) Circle
B) Parabola
C) Hyperbola
D) Ellipse
Show Answer
Answer:
Correct Answer: C
Solution:
Multiplying both, we get $ 3x^{2}-y^{2}=48 $ or $ \frac{x^{2}}{(48/3)}-\frac{y^{2}}{48}=1, $ which is a hyperbola.
BETA
