Conic Sections Question 43
Question: The equation of the parabola with focus (0, 0) and directrix $ x+y=4 $ is
[EAMCET 2003]
Options:
A) $ x^{2}+y^{2}-2xy+8x+8y-16=0 $
B) $ x^{2}+y^{2}-2xy+8x+8y=0 $
C) $ x^{2}+y^{2}+8x+8y-16=0 $
D) $ x^{2}-y^{2}+8x+8y-16=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ SP=PM\Rightarrow SP^{2}=PM^{2} $
therefore $ x^{2}+y^{2}={{( \frac{x+y-4}{\sqrt{2}} )}^{2}} $
therefore $ x^{2}+y^{2}-2xy+8x+8y-16=0. $
BETA
