Conic Sections Question 431
Question: The latus-rectum of the hyperbola $ 16x^{2}-9y^{2}= $
$ 144 $ , is
[MP PET 2000]
Options:
A) $ \frac{16}{3} $
B) $ \frac{32}{3} $
C) $ \frac{8}{3} $
D) $ \frac{4}{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
The given equation of hyperbola is $ 16x^{2}-9y^{2}=144 $
$ \Rightarrow \frac{x^{2}}{9}-\frac{y^{2}}{16}=1 $
L.R. $ =\frac{2b^{2}}{a} $ = $ \frac{2.16}{3}=\frac{32}{3} $ .
BETA
