[MP PET 1992]
A) $ \sqrt{2} $
B) 2
C) 3
D) $ \sqrt{3} $
Correct Answer: D
$ \frac{x^{2}}{(6/2)}-\frac{y^{2}}{6}=1 $
therefore $ a^{2}=3 $ and $ b^{2}=6 $
Therefore $ e=\sqrt{\frac{b^{2}}{a^{2}}+1} $
therefore $ e=\sqrt{3} $ .
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