Conic Sections Question 447
Question: The equation of a hyperbola, whose foci are (5, 0) and (-5, 0) and the length of whose conjugate axis is 8, is
Options:
A) $ 9x^{2}-16y^{2}=144 $
B) $ 16x^{2}-9y^{2}=144 $
C) $ 9x^{2}+16y^{2}=144 $
D) $ 16x^{2}-9y^{2}=12 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ b=4 $
therefore $ 2ae=10 $
therefore $ 16=25-a^{2} $
therefore $ a=3 $
Hence the hyperbola is $ 16x^{2}-9y^{2}=144 $ .
BETA
