SATHEE: Conic Sections Question 461

Conic Sections Question 461

Question: The eccentricity of the hyperbola $ \frac{\sqrt{1999}}{3}(x^{2}-y^{2})=1 $ is

[Karnataka CET 1999]

Options:

A) $ \sqrt{3} $

B) $ \sqrt{2} $

C) 2

D) $ 2\sqrt{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

Here $ a=b, $ so it is a rectangular hyperbola.

Hence, eccentricity $ e=\sqrt{2} $ .

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Conic Sections Question 461

Question: The eccentricity of the hyperbola $ \frac{\sqrt{1999}}{3}(x^{2}-y^{2})=1 $ is

Options:

Answer:

Solution:

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