Conic Sections Question 466
Question: Foci of the hyperbola $ \frac{x^{2}}{16}-\frac{{{(y-2)}^{2}}}{9}=1 $ are
Options:
A) (5, 2) (-5, 2)
B) (5, 2) (5, -2)
C) (5, 2) (-5, -2)
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ a=4,b=3 $
therefore $ \frac{9}{16}=(e^{2}-1) $
therefore $ e=\frac{5}{4} $
Vertex is (0, 2).
Hence focus is $ (\pm ae,2)=(\pm 5,2) $ .
BETA
