Conic Sections Question 467
Question: The equation of the hyperbola referred to the axis as axes of co-ordinate and whose distance between the foci is 16 and eccentricity is $ \sqrt{2} $ , is
[UPSEAT 2000]
Options:
A) $ x^{2}-y^{2}=16 $
B) $ x^{2}-y^{2}=32 $
C) $ x^{2}-2y^{2}=16 $
D) $ y^{2}-x^{2}=16 $
Show Answer
Answer:
Correct Answer: B
Solution:
According to question, Transverse axis = Conjugate axis Given that, $ e=\sqrt{2},2ae=16 $ ;$ a=4\sqrt{2} $
Therefore, equation of hyperbola is $ x^{2}-y^{2}=32. $
BETA
