Conic Sections Question 468
Question: The centre of the ellipse $ \frac{{{(x+y-2)}^{2}}}{9}+\frac{{{(x-y)}^{2}}}{16}=1 $ is
[EAMCET 1994]
Options:
A) (0, 0)
B) (1, 1)
C) (1, 0)
D) (0, 1)
Show Answer
Answer:
Correct Answer: B
Solution:
The centre of the given ellipse is the point of intersection of the lines $ x+y-2=0 $ and $ x-y=0 $ i.e.,(1,1).
BETA
