Conic Sections Question 48
Question: The equation of the tangents to the conic $ 3x^{2}-y^{2}=3 $ perpendicular to the line $ x+3y=2 $ is
Options:
A) $ y=3x\pm \sqrt{6} $
B) $ y=6x\pm \sqrt{3} $
C) $ y=x\pm \sqrt{6} $
D) $ y=3x\pm 6 $
Show Answer
Answer:
Correct Answer: A
Solution:
Tangent to $ \frac{x^{2}}{1}-\frac{y^{2}}{3}=1 $ and perpendicular to $ x+3y-2=0 $ is given by $ y=3x\pm \sqrt{9-3}=3x\pm \sqrt{6} $ .
BETA
