Conic Sections Question 485

Question: If a circle of constant radius 3k passes through the origin O and meets the coordinate axes at A and B, then the locus of the centroid of triangle OAB is

Options:

A) $ x^{2}+y^{2}={{(2k)}^{2}} $

B) $ x^{2}+y^{2}={{(3k)}^{2}} $

C) $ x^{2}+y^{2}={{(4k)}^{2}} $

D) $ x^{2}+y^{2}={{(6k)}^{2}} $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Let the centroid of triangle OAB be (p, q).

Hence, points A and B are (3p, 0) and (0, 3q), respectively. But diameter of the circle, AB=6k

Hence, $ \sqrt{9p^{2}+9q^{2}}=6k $ Therefore, the locus of (p, q) is $ x^{2}+y^{2}=4k^{2} $ .



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें