Conic Sections Question 49
Question: The equation of axis of the parabola $ 2x^{2}+5y-3x+4=0 $ is
[Pb. CET 2000]
Options:
A) $ x=\frac{3}{4} $
B) $ y=\frac{3}{4} $
C) $ x=-\frac{1}{2} $
D) $ x-3y=5 $
Show Answer
Answer:
Correct Answer: A
Solution:
Given equation of parabola is $ 2x^{2}+5y-3x+4=0 $
$ \Rightarrow $ $ x^{2}-\frac{3}{2}x=-\frac{5}{2}y-2 $
$ \Rightarrow $ $ {{( x-\frac{3}{4} )}^{2}}=-\frac{5}{2}y-\frac{23}{16} $
$ \therefore $ Equation of axis is, $ x-\frac{3}{4}=0 $
$ \Rightarrow $ $ x=\frac{3}{4} $
BETA
