Conic Sections Question 491
Question: The equation of the tangent to the ellipse $ x^{2}+16y^{2}=16 $ making an angle of $ 60^{o} $ with x-axis is
Options:
A) $ \sqrt{3}x-y+7=0 $
B) $ \sqrt{3}x-y-7=0 $
C) $ \sqrt{3}x-y\pm 7=0 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ m=\tan 60{}^\circ =\sqrt{3} $ . Therefore, equation of tangent is $ y=\sqrt{3}x\pm \sqrt{1+3\cdot 16} $
therefore $ y=\sqrt{3}x\pm 7 $ .
BETA
