SATHEE: Conic Sections Question 497

Conic Sections Question 497

Question: The focus of the parabola $ x^{2}=-16y $ is

[RPET 1987; MP PET 1988, 92]

Options:

A) (4, 0)

B) (0, 4)

C) (-4, 0)

D) (0, -4)

Show Answer

Answer:

Correct Answer: D

Solution:

$ a=4, $ vertex $ =(0,0) $ , focus $ =(0,-4) $ .

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Conic Sections Question 497

Question: The focus of the parabola $ x^{2}=-16y $ is

Options:

Answer:

Solution:

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