Conic Sections Question 5
Question: The length of the latus rectum of the parabola $ 9x^{2}-6x+36y+19=0 $
[MP PET 1994]
Options:
A) 36
B) 9
C) 6
D) 4
Show Answer
Answer:
Correct Answer: D
Solution:
$ 9x^{2}-6x+19=-36y $
therefore $ {{(3x-1)}^{2}}=-36y-18=-36( y+\frac{1}{2} ) $
therefore $ 9{{( x-\frac{1}{3} )}^{2}}=-36( y+\frac{1}{2} ) $
Hence length of latus rectum is 4.
BETA
