Conic Sections Question 500
Question: The ends of latus rectum of parabola $ x^{2}+8y=0 $ are
[MP PET 1995]
Options:
A) (-4, -2) and (4, 2)
B) (4, -2) and (-4, 2)
C) (-4, -2) and (4, -2)
D) (4, 2) and (-4, 2)
Show Answer
Answer:
Correct Answer: C
Solution:
$ x^{2}=-8y $
therefore $ a=-2 $ . So, focus $ =(0,-2) $
Ends of latus rectum $ =(4,-2),(-4,-2) $ .
Trick : Since the ends of latus rectum lie on parabola, so only points $ (-4,-2) $ and $ (4,-2) $ satisfy the parabola.
BETA
