Conic Sections Question 503
Question: The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point (6, -3) is
[MP PET 2001]
Options:
A) $ y^{2}=12x+6 $
B) $ x^{2}=12y $
C) $ x^{2}=-12y $
D) $ y^{2}=-12x+6 $
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Answer:
Correct Answer: C
Solution:
Since the axis of parabola is y-axis Equation of parabola $ x^{2}=4ay $
Since it passes through (6, - 3) 36 $ =-12a\Rightarrow a=-3 $
Equation of parabola is $ x^{2}=-12y $ .
BETA
