Conic Sections Question 508
Question: The equation of the parabola with focus (3, 0) and the directirx $ x+3=0 $ is
[EAMCET 2002]
Options:
A) $ y^{2}=3x $
B) $ y^{2}=2x $
C) $ y^{2}=12x $
D) $ y^{2}=6x $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \because $
$ SP^{2}=PM^{2} $
therefore $ {{(x-3)}^{2}}+y^{2}={{| \frac{x+3}{\sqrt{1}} |}^{2}} $
therefore $ x^{2}+9-6x+y^{2}=x^{2}+9+6x $
therefore $ y^{2}=12x $ .
BETA
