Conic Sections Question 51
Question: The equation of the tangent to the parabola $ y=x^{2}-x $ at the point where $ x=1 $ , is
[MP PET 1992]
Options:
A) $ y=-x-1 $
B) $ y=-x+1 $
C) $ y=x+1 $
D) $ y=x-1 $
Show Answer
Answer:
Correct Answer: D
Solution:
Point (1, 0)
therefore $ {{( \frac{dy}{dx} )} _{(1,0)}}=2-1=1 $
Hence the tangent is $ y-0=x-1 $ .
BETA
