Conic Sections Question 512

Question: The equation of latus rectum of a parabola is $ x+y=8 $ and the equation of the tangent at the vertex is $ x+y=12 $ , then length of the latus rectum is

[MP PET 2002]

Options:

A) $ 4\sqrt{2} $

B) $ 2\sqrt{2} $

C) 8

D) $ 8\sqrt{2} $

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Answer:

Correct Answer: D

Solution:

Clearly; $ a=| \frac{-8}{\sqrt{1+1}} |-| \frac{-12}{\sqrt{1+1}} |=\frac{4}{\sqrt{2}} $

Length of latus rectum = 4a $ =4\times \frac{4}{\sqrt{2}}=8\sqrt{2} $ .