SATHEE: Conic Sections Question 514

Conic Sections Question 514

Question: Vertex of the parabola $ y^{2}+2y+x=0 $ lies in the quadrant

[MP PET 1989]

Options:

A) First

B) Second

C) Third

D) Fourth

Show Answer

Answer:

Correct Answer: D

Solution:

Given parabola can be written as $ {{(y+1)}^{2}}=-(x-1) $ .

Hence vertex is (1, -1), which lies in IV quadrant.

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Conic Sections Question 514

Question: Vertex of the parabola $ y^{2}+2y+x=0 $ lies in the quadrant

Options:

Answer:

Solution:

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